(4x-3)(x^2-5x+1)=

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Solution for (4x-3)(x^2-5x+1)= equation: 


Simplifying
(4x + -3)(x2 + -5x + 1) = 0

Reorder the terms:
(-3 + 4x)(x2 + -5x + 1) = 0

Reorder the terms:
(-3 + 4x)(1 + -5x + x2) = 0

Multiply (-3 + 4x) * (1 + -5x + x2)
(-3(1 + -5x + x2) + 4x * (1 + -5x + x2)) = 0
((1 * -3 + -5x * -3 + x2 * -3) + 4x * (1 + -5x + x2)) = 0
((-3 + 15x + -3x2) + 4x * (1 + -5x + x2)) = 0
(-3 + 15x + -3x2 + (1 * 4x + -5x * 4x + x2 * 4x)) = 0
(-3 + 15x + -3x2 + (4x + -20x2 + 4x3)) = 0

Reorder the terms:
(-3 + 15x + 4x + -3x2 + -20x2 + 4x3) = 0

Combine like terms: 15x + 4x = 19x
(-3 + 19x + -3x2 + -20x2 + 4x3) = 0

Combine like terms: -3x2 + -20x2 = -23x2
(-3 + 19x + -23x2 + 4x3) = 0

Solving
-3 + 19x + -23x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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